Question
If the product of three consecutive natural numbers is
93024, then find the sum of the three given natural numbers.Solution
ATQ,
Let the three natural numbers be βaβ, βbβ, and βcβ.
ATQ,
a Γ b Γ c = 93024
93024 = 4 Γ 6 Γ 8 Γ 11 Γ 11
One of the numbers is 44, and the other two are 43 and 45
So, the three consecutive natural numbers are 43, 44, and 45
So, the required sum = 43 + 44 + 45 = 132
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