Question
Find remainder when 7103 is divided by 240.
Solution
ATQ,
Ο(240)=64 β 7βΆβ΄ β‘ 1 mod 240 103 = 64+39 β remainder = 7Β³βΉ mod 240 Cycle of 7 mod 16 = 7, 1 β mod16=7 mod15: 7β΄ β‘ 1 β so mod15=7Β³ β‘13 Combine via CRT β remainder 103.
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