Question
A 160 m long train crosses another 280 m long train
running in the opposite direction in 11 seconds. If the shorter train crosses a pole in 8 seconds, what is the speed of longer train?Solution
Speed of the shorter train = 160/8 = 20 m/sec Let the speed of the longer train be x km/hr According to the question, β (20 + x) = (160 + 280)/11 β 20 + x = 440/11 β x = 40 β 20 = 20 β x = 20 x 18/5 = 72 km/hr
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