Question
A, B and C can individually complete a piece of work in
24 days, 15 days and 12 days,respectively. B and C started the work and worked for 3 days and left. The number of days required by A alone to complete the remaining work, is:Solution
Let the total work be 120 units. (LCM of 24, 15 and 12 is 120.) Efficiency of A = work/time = 120/24 = 5 units/day Efficiency of B = 120/15 = 8 units/day Efficiency of C = 120/12 = 10 units/day Work done by B and C in 3 days = (8 + 10) 3 = 54 units Remaining work = 120 - 54 = 66 units Time taken by A to complete the remaining work = 66/5 = 13(1/5)
More Time Questions
(350/?) = 23 + 33
(630 ÷ 35) × 2 + 144 = ? × 2
?/4 ÷ 9/? = 15% of 800 + `1(2/3)` × `1(1/5)` × 1/2
236.23-653.23+696.23=?
72 × 2 = ? + 104 – 14
36895 - 4256 - 2233 = ?
What will come in the place of question mark (?) in the given expression?
3.6 X 15 + 4.5 X 12 = 40% of (? - 50)? = 15% of 2400 + 140% of 4200 – 12 3
√121 + √961− √289 =?2
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