Question
A, B and C can individually complete a piece of work in
24 days, 15 days and 12 days,respectively. B and C started the work and worked for 3 days and left. The number of days required by A alone to complete the remaining work, is:Solution
Let the total work be 120 units. (LCM of 24, 15 and 12 is 120.) Efficiency of A = work/time = 120/24 = 5 units/day Efficiency of B = 120/15 = 8 units/day Efficiency of C = 120/12 = 10 units/day Work done by B and C in 3 days = (8 + 10) 3 = 54 units Remaining work = 120 - 54 = 66 units Time taken by A to complete the remaining work = 66/5 = 13(1/5)
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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