Question
A man, a woman and a boy can do a work in 4, 8, 16 days
respectively. How many boys were required with 1 man and 1 woman to complete the same work in 1/2 day?Solution
Work done by a man in (1 )/(2 )days = (1 )/(8 )part Work done by a woman in (1 )/(2 )days = (1 )/(16 )part Work done by a boy in (1 )/(2 )days = (1 )/(32 )part Let one man and one woman together can do a piece of work in (1 )/(2 )days = No. of x boys required According to the question, (1 )/(8 )+ (1 )/(16 ) + x/(32 ) = 1 (4 +2+ x )/(32 ) = 1 6 + x = 32 x = 32 – 6 = 26 Hence, 26 boys will be required.
35.25 71 146 296 624 1376
...22   39    58    81   ?      141
1 9 64 255 755 1835
...Find the odd one out: 11, 13, 17, 19, 21
32 63 121 ? 453 889
...1,2, 5, ‘?’, 41, 122, 365
7Â Â Â Â Â Â 15Â Â Â Â Â Â Â 31Â Â Â Â Â Â 63Â Â Â Â Â Â 127Â Â Â Â Â Â ?
...122, 116, 125, 119, 128, ?
13, 14, 18, 27, 43, ?
38    40    83    254    ?     5126
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