Question
Worker βPβ can complete a job in 30 days, and
together with βQβ, they can finish it in 12 days. If βQβ worked alone for 15 days and then stopped, how long will βPβ take to finish the remaining work?Solution
Let the total work = 60 units {L.C.M of 30 and 12}
Then, efficiency of βPβ = 60 Γ· 30 = 2 units/day
Combined efficiency of βPβ and βQβ = 60 Γ· 12 = 5 units/day
So, efficiency of βQβ = 5 β 2 = 3 units/day
So, work done by βQβ alone in 15 days = 3 Γ 15 = 45 units
Remaining work = 60 β 45 = 15 units
Time taken by 'P' alone to complete the remaining work = 15 Γ· 2 = 7.5 days
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