Question
Worker ‘P’ can complete a job in 30 days, and
together with ‘Q’, they can finish it in 12 days. If ‘Q’ worked alone for 15 days and then stopped, how long will ‘P’ take to finish the remaining work?Solution
Let the total work = 60 units {L.C.M of 30 and 12}
Then, efficiency of ‘P’ = 60 ÷ 30 = 2 units/day
Combined efficiency of ‘P’ and ‘Q’ = 60 ÷ 12 = 5 units/day
So, efficiency of ‘Q’ = 5 – 2 = 3 units/day
So, work done by ‘Q’ alone in 15 days = 3 × 15 = 45 units
Remaining work = 60 – 45 = 15 units
Time taken by 'P' alone to complete the remaining work = 15 ÷ 2 = 7.5 days
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