Question
‘P’ and ‘Q’ can complete a task together in 30
days. If ‘P’ is 60% more efficient than ‘Q’, how many days will ‘Q’ take to finish the work alone?Solution
Let the efficiency of ‘Q’ be 10x units. Efficiency of ‘P’ = 10x × 1.6 = 16x units Total work = 30 × (10x + 16x) = 780x units Time taken by ‘Q’ alone = 780x ÷ 10x = 78 days
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