Question
βPβ and βQβ can complete a task together in 30
days. If βPβ is 60% more efficient than βQβ, how many days will βQβ take to finish the work alone?Solution
Let the efficiency of βQβ be 10x units. Efficiency of βPβ = 10x Γ 1.6 = 16x units Total work = 30 Γ (10x + 16x) = 780x units Time taken by βQβ alone = 780x Γ· 10x = 78 days
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