Question
X and Y can complete a piece of work in 20 days. They
worked for 10 days and left. Z completed the rest of the work in 10 days. Find how long Z would take to finish 60% of the same work alone.Solution
ATQ,
Fraction of Work done by X and Y = (10/20) = (1/2)
Fraction of work done by Z = 1 - (1/2) = (1/2)
So, number of days taken by Z alone to complete the entire work = 10 ÷ (1/2) = 20 days
So, time taken by Z to complete 60% of the work = 20 × 0.60 = 12 days
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