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Let the total work be 180 units. {LCM (36 and 60)}
So, combined efficiency of 'C' and 'D' = 180 ÷ 36 = 5 units/day
Efficiency of 'C' = 180 ÷ 60 = 3 units/day
So, efficiency of 'D' = 5 - 3 = 2 units/day
So, time taken by 'D' to do the work alone = 180 ÷ 2 = 90 days
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