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Let the capacity of the tank = L.C.M and 15 and 21 = 105 units
Then, efficiency of the inlet pipe = 105 ÷ 15 = 7 units/minute
Combined efficiency of the inlet pipe with the leak = 105 ÷ 21 = 5 units/minute
So, efficiency of the leak = 5 - 7 = 2 units/minute (outlet)
So, time taken by the leak to empty the entire tank = 105 ÷ 2 = 52.5 minutes
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