Question
Person A is 40% more efficient than person B, while person
C is 40% less efficient than person B. All three—A, B, and C—can together finish a task in 35 days. If only A and B work on the task for the first 40 days, how many additional days will C alone need to complete the remaining work?Solution
Let efficiency of ‘B’ is ‘x’ units per day
Efficiency of ‘A’ = 1.40 × x = 1.4x units per day
Efficiency of ‘C’ = 0.60 × x = 0.6x units per day
Total work = (1.4x + x + 0.6x) × 35 = 105x units
Amount of work done by ‘A’ and ‘B’ together in 40 days = 40 × (1.4x + x) = 96x units
Desired time = (105x – 96x)/0.6x = 15 days
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