Question
Two efficient workers or three non-efficient workers can
complete a certain task in 20 days. If each efficient worker improves their efficiency by 33(1/3)% and each non-efficient worker reduces their efficiency by 50%, how long will it take for a team of two efficient workers and two non-efficient workers, under these new conditions, to finish the same task?Solution
Let the efficiencies of an efficient worker and a non-efficient worker be 'x' units/day and 'y' units/day respectively. ATQ, 2x X 20 = 3y X 20 Or, x:y = 3:2 Let x = 3a and y = 2a So, total work = 2 X 3a X 20 = 120a units Increased efficiency of an efficient worker = 3a X (4/3) = 4a units/day Decreased efficiency of a non-efficient worker = 2a X (1/2) = 'a' unit/day Therefore, required time = 120a Γ· (2 X 4a + 2 X a) = (120a Γ· 10a) = 12 days
- Find the simplified value of the given expression.
Find the simplified value of the given expression
((9.77)0- γ(0.1)γ(-1))/(γ(6/24 )γ(-1)Β Γ(3/2)3+ γ((-2)/6)γ(-1) ) = ?
...1111.25 × 9.05 + 2323.23 × 9.05 – 2121.37 ×9.05 =?
15.50% of 6240 β 426.31 = ?Β
8 Γ 25% of ? = 400
Simplify the following expressions and choose the correct option.
45% of 640 + (2/5 of 350) = ?
What will come in the place of question mark (?) in the given expression?
(20% of 820 β 56 + 11 Γ 8) 1/2 = ? β 62
24% of 400 × 16% of ? = 384
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