Question
Two efficient workers or three non-efficient workers can
complete a certain task in 20 days. If each efficient worker improves their efficiency by 33(1/3)% and each non-efficient worker reduces their efficiency by 50%, how long will it take for a team of two efficient workers and two non-efficient workers, under these new conditions, to finish the same task?Solution
Let the efficiencies of an efficient worker and a non-efficient worker be 'x' units/day and 'y' units/day respectively. ATQ, 2x X 20 = 3y X 20 Or, x:y = 3:2 Let x = 3a and y = 2a So, total work = 2 X 3a X 20 = 120a units Increased efficiency of an efficient worker = 3a X (4/3) = 4a units/day Decreased efficiency of a non-efficient worker = 2a X (1/2) = 'a' unit/day Therefore, required time = 120a ÷ (2 X 4a + 2 X a) = (120a ÷ 10a) = 12 days
10.10% of 999.99 + 14.14 × 21.21 - 250.25 = ?
56.05 2 – 24.24 2 + (63.98) 3/2 – 32.28% of 1500 = ? 2 + 113.03 × 5.09Â
What will be the approximate value of the following questions.
125.9% ÷ 9.05 x 99.98 = ? - 69.97 × √324.02 ÷ 5.98
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(98.03 + 186.98) ÷ 19.211 = 89.9 – 20.23% of ?
11.232 + 29.98% of 599.99 = ? × 6.99
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
(899.78 ÷ 15.11) × (√143.94 + 10.02) – 230...
(36.35 × 14.89) ÷ 8.78 = ? – 59.98
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