Question
'A' takes 7 times as much time as 'B' takes or 3 times
as much time as 'C' takes to finish a piece of work. Working together, they can finish the work in 21 days. 'B' can do the work alone in:Solution
Let the time taken by 'B' be '3x' days Therefore, time taken by 'A' = 7 X 3x = '21x' days Time taken by 'C' = (21x/3) = '7x' days Let total work = 21x units {LCM of '3x, '21x' and '7x'} Efficiency of 'A' = (21x/21x) = 1 unit/day Efficiency of 'B' = (21x/3x) = 7 units/day Efficiency of 'C' = (21x/7x) = 3 units/day Combined efficiency of 'A', 'B' and 'C' = (21x/21) = 'x' units/day Or, x = 1 + 7 + 3 = 11 Therefore, time taken by 'B' = 3x = 33 days
10,14,26,42,70,?
If series II follows the same sequence pattern as series I shown below, determine the value of 'p'.
Series I: 40, 25, 30, 50, 105, 267.5
<...6, 7, 15, 46, 185, ?
3, 8, 27, 124, ?
What will come in place of the question mark (?) in the following series?
17, 138, 307, 532, ?, 1182
250 Â Â Â 25 Â Â Â Â 5 Â Â Â Â ? Â Â Â Â 0.6 Â Â Â Â Â 0.3
Find the missing number, in the given number series.
25, 30, 40, 57, ?, 120
What will come in place of the question mark (?) in the following series?
121, 110, 97, ?, 61, 38
110, 156, 212, ?, 354, 440
17, 19, 41, 127, 513, ?Â
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