Question
Four number pair have been given, out of which three are
alike in a certain way and one is different. Select the one that is different. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g., 13 - operation on 13 such as adding/subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed)Solution
The logic followed here is: Second number = (First number)² - 4. Option 'A': 10 – 96 → 10² - 4 = 100 - 4 = 96 Option 'B': 14 – 192 → 14² - 4 = 196 - 4 = 192 Option 'C': 16 – 252 → 16² - 4 = 256 - 4 = 252 Option 'D': 20 – 396 → 20² - 4 = 400 - 4 = 396
I. 6x² + 37x + 45 = 0
II. 3y² - 11y + 6 = 0
I. 3y² - 20y + 25 = 0
II. 3x² - 8x + 5 = 0
if x satisfies 3x² – 5x – 12 = 0, find the sum of reciprocals of roots.
I. 96x² + 52x - 63 = 0
II. 77y² + 155y + 72 = 0
I. 2x2 - 5x - 33 =0
II. 2y2 + 5y - 25 = 0
Equation 1: x² - 180x + 8100 = 0
Equation 2: y² - 170y + 7225 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 41x² - 191x + 150 = 0
Equation 2: 43y² - 191y + ...
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
Roots of the quadratic equation 2x2 + x – 528 = 0 is
I. 4x² -  15x + 9 = 0
II. 20y² -  23y + 6 = 0