Question
A is capable of finishing a task in 60 days. B requires
40% more time than A to finish the same task. How many days will A and B need to complete 80% of the work together?Solution
Time taken by B to complete the whole work = 1.40 × 60 = 84 days Let total work = 420 units (LCM of 60 and 84) Efficiency of A = 420/60 = 7 units per day Efficiency of B = 420/84 = 5 units per day Desired time = (0.80 × 420)/12 = 28 days
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