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    Question

    'A' alone can finish a job in 12 days. If 'A' is twice

    as efficient as 'B' who is 20% as efficient as 'C', then find the time taken to finish the job if they all work together.
    A 3 days Correct Answer Incorrect Answer
    B 4 days Correct Answer Incorrect Answer
    C 4.5 days Correct Answer Incorrect Answer
    D 6 days Correct Answer Incorrect Answer

    Solution

    Let the total work be '24x' units. Efficiency of 'A' = (24x/12) = '2x' units/day Efficiency of 'B' = (2x X 0.5) = 'x' unit/day Efficiency of 'C' = (x ÷ 0.2) = '5x' units/day Time taken to finish the work when all 'A', 'B' and 'C' work together = {24x/(2x + x + 5x)} = 3 days

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