Question
If 6 men and 5 boys can complete a piece of work in 9
days, while 24 men and 20 boys can complete the same work in 3 days, how long will it take for 12 men and 15 boys to complete the same work?Solution
Let the efficiency of a man be βpβ units per day and the efficiency of a boy be βqβ units per day. According to the question: (6p + 5q) Γ 9 = (24p + 20q) Γ 3 Or, 54p + 45q = 72p + 60q Or, 15q = 18p Or, q = 1.2p Total work = (6p + 5q) Γ 9 = (6p + 6p) Γ 9 = 12p Γ 9 = β108pβ units Efficiency of 12 men and 15 boys = 12p + 15q = 12p + 18p = 30p units per day Required time = (108p / 30p) = 3.6 days
((67)32 × (67)-18 / ? = (67)βΈ
What will come in the place of question mark (?) in the given expression?
?% of (112 X 3 + 164) + 75 = 2 X 140 + 35
20% of 450 - 15% of 400 = 25% of ?
β121 + β961β β289 =?2
45% of 1020 + ?% of 960 = 747
(γ(0.4)γ^(1/3)Β Γ γ(1/64)γ^(1/4)Β Γ γ16γ^(1/6)Β Γ γ(0.256)γ^(2/3))/(γ(0.16)γ^(2/3)Β Γ 4^(-1/2)Β Γγ1024γ^(-1/4) ) = ?
(512) (2/3) Γ β64 Γ· (512) (1/3) = (64) (?/2) Γ· (2)6Β
1231 + 1312 + 2113 β 3211 = ?
Simplify the following expression:-
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