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      Question

      'Sita' can complete some work alone in 20 days. 'Geeta'

      is twice as efficient as 'Reeta' and three times as efficient as 'Sita'. If 'Sita' and 'Reeta' start working together, then after how many days should 'Geeta' replace them so that the work gets completed in exactly 8 days?
      A 5 days Correct Answer Incorrect Answer
      B 12 days Correct Answer Incorrect Answer
      C 8 days Correct Answer Incorrect Answer
      D 10 days Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      Sita's rate = 1/20 Geeta = 3 ├Ч Sita тЖТ 3/20 Geeta = 2 ├Ч Reeta тЖТ Reeta = 3/40 Sita + Reeta = 1/20 + 3/40 = (2 + 3)/40 = 1/8 Let Geeta join after x days: Work by Sita & Reeta = x ├Ч 1/8 = x/8 Work by Geeta = (8 тИТ x) ├Ч 3/20 Total work = 1: x/8 + (8 тИТ x) ├Ч 3/20 = 1 тЖТ (тИТ x + 48)/40 = 1 тЖТ x = 8 Hence, Geeta should replace them after 8 days (i.e., not needed at all)

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