Question
If a sum of money invested on simple interest becomes 4
times of itself at 'R%' p.a. in 6 years, then find the value of '0.4R'.Solution
Let the sum invested be Rs. 'P'. Simple interest earned = 4P - P = Rs. '3P' Simple interest = Principal X (rate/100) X time period in years So, 3P = P X (R/100) X 6 Or, 'R' = (300/6) = 50 Therefore, required value = '0.4R' =0.4 X 50 = 20
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