Question
R' invested some money at a compound interest rate of
40% p.a., compounded quarterly. If after 9 months, he received an amount of Rs. 1,99,650, then the sum invested by 'R' is equal to: I. The interest received when Rs. 1,25,000 is invested at S.I of 30% p.a. for 4 years. II. The C.P of an item sold for Rs. 2,40,000 at a profit of 40%. III. The difference between the savings of 'Pawan' and 'Qureshi', whose incomes are Rs. (a + 406320) and Rs. (a + 156320), given that each spends 40% of their respective incomes.Solution
ATQ, Effective rate of interest = 40 ÷ 4 = 10% p.a. And effective time period = (9/12) × 4 = 3 terms We know that for compound interest, Amount = Sum × {1 + (rate of interest/100)} time period Let the sum invested be Rs. 'S' So, 199650 = S X {1 + (10/100)} ³ Or, 199650 = S X (1.1) ³ Or, 199650 = 1.331S So, S = 1,50,000 Therefore, sum invested = Rs. 1,50,000 For I: Interest received = (125000 × 0.3 × 4) = Rs. 1,50,000 Therefore, statement I is true. For II: CP of the item = (240000/1.4) = Rs. 171428.57 Therefore, statement II is false. For III: Difference between savings of 'Pawan' and 'Qureshi' = 0.6 × (a + 406320) - 0.6 × (a + 156320) = 0.6 × (406320 - 156320) = 0.6 × 250000 = Rs. 1,50,000 Therefore, statement III is true.
- Find the wrong number in the given number series.
5, 10, 20, 35, 80, 160 - Find the wrong number in the given number series.
2, 10, 12, 36, 38, 34 Find the wrong number in the given number series.
30, 17, 19, 30.5, 64, 164.5
121Â Â Â Â Â 127Â Â Â Â Â Â 133Â Â Â Â Â Â 142Â Â Â Â Â Â 160Â Â Â Â Â Â 206
...6.5, 11, 22, 25.5, 51, 54.5
- Find the wrong number in the given number series.
25, 36, 29, 40, 33, 50 123, 155, 198, 246, 301, 363Â
14, 16, 22, 46, 172, 886
12, 18, 40, 90, 270, 945
Find the wrong number, in the given number series,
1680, 840, 2520, 630, 3150, 475