Question
Amit placed an amount 'p' in Fund 'X' that offers a 10%
compound interest per annum and also invested Rs. (p + 1000) in Fund 'Y' that offers a 15% simple interest per annum. Both investments were made for a duration of 2 years. If the combined interest received from these investments totals Rs. 810, calculate the value of '2p'.Solution
ATQ, At compound interest (compounded annually) , Interest received = Sum invested × {1 + (rate/100) } - sum invested So, interest received from Fund 'X' = 'p' × {1 + (10/100) }²- p = 1.21p - p = Rs. 0.21p Simple interest = (sum invested × rate × time) ÷ 100 So, interest received from Fund 'Y' = {(p + 1000) × 15 × 2} ÷ 100 = 0.3 × (p + 1000) = Rs. (0.3p + 300) ATQ; 0.21p + 0.3p + 300 = 810 So, 0.51p + 300 = 810 Or, 0.51p = 810 - 300 Or, 0.51p = 510 Or, 'p' = 1000 So, 2p = 2× 1000 = 2000
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 20x + 96 = 0
Equation 2: y² - 18y + 72 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 21x² - 82x + 80 = 0
Equation 2: 23y² - 132y + 85 = 0
I. x= √(20+ √(20+ √(20+ √(20…………….∞)) ) )
II. y= √(5√(5√(5√(5……….∞)) ) )
...I. 10x2 + 33x + 9 = 0
II. 2y2 + 13y + 21 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
...I). p2 + 22p + 72 = 0,
II). q2 - 24q + 128 = 0
I. 2x2 – 5x - 12 = 0
II. y2 – 11y + 30 = 0
I. 2x2 – 19x + 45 = 0
II. y2 – 14y + 48 = 0
I. 104x² + 9x - 35 = 0
II. 72y² - 85y + 25 = 0
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