Start learning 50% faster. Sign in now
Ratio of efficiency of Divya: Vivek = 125:100 = 5: 4 Efficiency of Sanjay = 4 × (1/2) = 2 units/day According to question, (5 × (120/100) + 4) x / (4 + 2) (x + 10) = 5/7 10x / (6x + 60) = 5/7 70x – 30x = 300 x = 7.5days Total work = (10 × 7.5) + (6 × 17.5) = 75+105 = 180 ATQ-Rajeev efficiency = (Divya + Vivek) = 9 units/day Sanjay and Rajeev efficiency = (2 + 9) = 11 units/day (Sanjay + Rajeev) = 180/11 days
Speed of a boat in still water to speed of boat in upstream is 9:5. If the boat can travel 390 km in downstream in 5 hours, then find the time taken by ...
Boat ‘A’ can cover 160 km in still water in 8 hours. In still water, if the ratio of the speed of boat ‘A’ to that of ‘B’ is 4:3 and the spe...
The ratio of the speed of the boat in upstream to that of in downstream is 5:9, respectively. If the speed of the current is 7 km/h, then find the speed...
A boat can travel 80 km downstream in 4 hours and the same distance upstream in 8 hours. If the speed of the boat in still water is increased by 50%, ho...
Boat ‘A’ can cover 120 km in still water in 10 hours. In still water, if the ratio of the speed of boat ‘A’ to that of ‘B’ is 4:5 and the sp...
Speed of a boat in still water is 10 kmph and speed of stream is 6 kmph. A man rows to a place at a distance of 32 km and come back to starting point. T...
A boat travels 315 km downstream in 7 hours and 135 km upstream in 9 hours. Determine the total time the boat takes to cover 150 ...
A boat travels from point 'T' to point 'S' downstream and returns upstream in a total of 32 hours. The speed of the boat in upstream is three times the ...
If a man rows at the rate of 25 kmph in still water and his rate against the current is 5.5 kmph, then the manrsquo;s rate along the current is...