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    Question

    'Alex,' 'Ben,' and 'Charlie' can individually complete a

    task in 40, 60, and 100 days, respectively. They decide to work together, but there's a unique pattern: 'Alex' works every day, 'Ben' joins in on odd-numbered days, and 'Charlie' on even-numbered days. Calculate the time required to finish the entire task following this alternating work schedule.
    A 26(2/5) Correct Answer Incorrect Answer
    B 26(3/5) Correct Answer Incorrect Answer
    C 26(4/5) Correct Answer Incorrect Answer
    D 26(7/5) Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Let the total work be 600 units. {LCM (40, 60 and 100)} So, efficiency of 'Alex' = 600 ÷ 40 = 15 units/day And efficiency of 'Ben' = 600 ÷ 60 = 10 units/day And efficiency of 'Charlie' = 600 ÷ 100 = 6 units/day So, work done in every 2 days = (15 × 2) + 10 + 6 = 46 units/day So, work done in 26 days = (26/2) × 46 = 598 units And time taken by 'Alex' and 'Ben' together to finish the remaining work on last day = {(600-598)/(15+10)} So, total time taken = 26 + (2/25) =26(2/5)

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