'Alex,' 'Ben,' and 'Charlie' can individually complete a task in 40, 60, and 100 days, respectively. They decide to work together, but there's a unique pattern: 'Alex' works every day, 'Ben' joins in on odd-numbered days, and 'Charlie' on even-numbered days. Calculate the time required to finish the entire task following this alternating work schedule.
ATQ, Let the total work be 600 units. {LCM (40, 60 and 100)} So, efficiency of 'Alex' = 600 ÷ 40 = 15 units/day And efficiency of 'Ben' = 600 ÷ 60 = 10 units/day And efficiency of 'Charlie' = 600 ÷ 100 = 6 units/day So, work done in every 2 days = (15 × 2) + 10 + 6 = 46 units/day So, work done in 26 days = (26/2) × 46 = 598 units And time taken by 'Alex' and 'Ben' together to finish the remaining work on last day = {(600-598)/(15+10)} So, total time taken = 26 + (2/25) =26(2/5)
200 ? 96 38.4 7.68 0
11 20 ? 64 112 192
...69, 35.5, 39.5, 68.25, 152.5, ?
10, 10, 15, 30, 75, ?
16, 9, ?, 114.25, 750.625, 6396.3125
43 86 258 ? 5160 30960
...3 4 10 33 136 ?
...14.8% of 7200 – 16.4% of 6200 + 15.09% of 8100 = 10% of ?
16, 8, 8, 12, ?, 60
24, 35, 48, 65, 84, 107