Question
'A' and 'B' together can do some work in 15 days. 'A'
however is 30% more efficient than 'B'. If 'A' and 'B' started the work alone but 'A' left after working for 10 days, then how much time (in days) would 'B' need to finish the remaining work?Solution
Let the efficiency of 'B' be 'x' units/day So, efficiency of 'A' = x × 1.3 = '1.3x' units/day So, total work = (1.3x + x) × 15 = '34.5x' units Work done in 10 days = 10 × (1.3x + x) = '23x' units So, work remaining = 34.5x - 23x = '11.5x' units So, time taken by 'B' to finish the remaining work = 11.5x ÷ x = 11.5 days
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