Question
A can complete a work in 10 days. B takes 4 days less
than A to complete the same work. In how many days can both of them together complete 80% of the work together?Solution
Time taken by B to complete the work = 10 – 4 = 6 days Let the total work = 30 units Efficiency of A = 30/10 = 3 units/day Efficiency of B = 30/6 = 5 units/day Required time taken = 0.80 x 30/(3+5) = 3 days
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