Question
βAβ alone can complete a work in 12 days. βBβ
alone can complete the same work in 24 days. If βAβ and βBβ work together for 4 days, then the remaining work can be completed by βAβ alone in how many days?Solution
Let the total amount of work = 24 units {LCM of 12 and 24} Then, efficiency of βAβ = 24/12 = 2 units/day Efficiency of βBβ = 24/24 = 1 units/day Combined efficiency of βAβ and βBβ = 2 + 1 = 3 units/day Work completed by βAβ and βBβ together in 4 days = 3 Γ 4 = 12 units Remaining work = 24 β 12 = 12 units Time taken by βAβ alone to complete the remaining work = 12/2 = 6 days
9.992 + (6.01 Γ 7.98) + ? = 320.03
564.932 + 849.029 β 425.08 = 612.095 + ?
319.995 Γ 15.98 Γ· 4.002 - ? Γ 7.95 = 1679.89 Γ· 2.005
The number of men, women and children in a village are in the ratio of 3:2:5 respectively. If total population of men is 2700, then find the average pop...
1314.04 β 450.18 + 359.98 Γ· 12.06 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
85.22 of 499.98% + 299.99 Γ· 30.18 = ?
29.88% of 3599.90 + 5/12 of 2399.81 β 34.81% of 1200.18 = ?
? + 96.18 – 15.02 = 118.98 + 31.09