Question
βAβ alone can complete a work in 12 days. βBβ
alone can complete the same work in 24 days. If βAβ and βBβ work together for 4 days, then the remaining work can be completed by βAβ alone in how many days?Solution
Let the total amount of work = 24 units {LCM of 12 and 24} Then, efficiency of βAβ = 24/12 = 2 units/day Efficiency of βBβ = 24/24 = 1 units/day Combined efficiency of βAβ and βBβ = 2 + 1 = 3 units/day Work completed by βAβ and βBβ together in 4 days = 3 Γ 4 = 12 units Remaining work = 24 β 12 = 12 units Time taken by βAβ alone to complete the remaining work = 12/2 = 6 days
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