Question
Match the Column I with Column II and select the correct
answer using the codes given below: Column I (Molecule) A. Proteins B. Carbohydrates C. Nucleic acids D. Lipids Column II (Product of Digestion) Nitrogenous bases and pentose sugars Fatty acids and glycerol Monosaccharides Amino acidsSolution
- Proteins (A): Digested into amino acids (4) by enzymes like pepsin and trypsin.
- Carbohydrates (B): Broken down into monosaccharides (3) like glucose by enzymes such as amylase.
- Nucleic acids (C): Digested into nitrogenous bases and pentose sugars (1) by nucleases.
- Lipids (D): Broken down into fatty acids and glycerol (2) by lipases.
- Digestion involves the breakdown of macromolecules into absorbable units.
- Proteins require stomach acids and proteolytic enzymes.
- Carbohydrates start digestion in the mouth with salivary amylase.
- Lipids are emulsified by bile salts for efficient enzyme action.
- Nucleic acids are digested in the small intestine.
Which of the following set of elements should be placed in the place of question marks respectively (in same order from left to right) in order to compl...
In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is /are definitely true and then...
In the question, assume the given statements to be true. Find which of the following conclusion(s) among the three conclusions is/ are definitely true ...
Statements: A > B > C; D < E < C; D ≥ F = G
Conclusion:
I. G < E
II. F < A
Statements:Â
A $ B * X © Y @ ZÂ
Conclusions:Â
I. X @ ZÂ
 II. Z * AÂ
III. Z % X
In which of the following expressions will the expression ‘S > Y’ and ‘R > Y be definitely true?
Statements: T > S > R, L ≥ D < R, L ≤ O ≤ Z
Conclusions:
I. T > L
II. S > D
III. Z ≥ R
...In the following question, a relationship between different elements is shown in the statements, followed by two conclusions I and II. Assuming the stat...
Statements: A > Y = D > Q, M ≤ B > P > Y
Conclusion:
I. Y ≤ M
II. B > QÂ Â
Statement: L ≥ X ≤ Z > Y ≤ A, Y = B ≥ CÂ
Conclusion: I. C >A                         II. A ≥ C
...
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