A mass m is suspended from a spring of spring constant k and oscillates with amplitude
A. The maximum velocity during oscillation is:

Rationale: The motion of a mass-spring system undergoing simple harmonic motion (SHM) is described by the equation x(t) = Acos ( ωt +  φ),   where x(t) is the displacement from the equilibrium position, A is the amplitude, ω is the angular frequency, and ϕ is the phase constant. The velocity of the mass is the first derivative of the displacement with respect to time: The maximum value of the velocity occurs when ∣ sin(ωt + ϕ) ∣ is maximum, which is 1. Therefore, the magnitude of the maximum velocity (vmax​) is: Therefore, the correct answer is option (d).