Question
βAβ and βBβ can do a piece of work in 10 days
and 15 days, respectively. They started working together but βAβ left after 3 days. Find the time taken by βBβ to complete the remaining work.Solution
Let total amount of work be 30 units (LCM of 10 and 15). Efficiency of βAβ = 30/10 = 3 units/day Efficiency of βBβ = 30/15 = 2 units/day Amount of work done by βAβ and βBβ together in 3 days = (3 + 2) Γ 3 = 15 units Time taken by B to complete remaining work = {(30 β 15)/2} = 7.5 days
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