Question
The time taken by ‘A’ to build a wall alone is 60%
more than the time taken by him to build it along with ‘B’. ‘B’ will take how much percent more time to build the same wall than the time taken by him to build it along with ‘A’?Solution
Let the work ‘A’ and ‘B’, can do in 1 day be ‘a’ units and ‘b’ units, respectively. Let they takes ‘p’ days to build the wall, together Therefore, Total work = (a + b) × p units …….. (1) According to the question, Time taken by ‘A’ to build the wall alone = 1.6p days Therefore, total work = 1.6p × a units….. (2) From equation (1) and (2), we get 5b/3 = a Therefore, total work to be done = (a + b) × p = 8bp/3 units Time taken by 'B' to build the wall = 8bp/3b = 8p/3 days Therefore, required percentage = (8p/3 – p)/p} × 100 = 166.66% more time
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(804/65) ÷ (11/798) × (129/131) = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(8000)1/3 × 10.11 × 8.97 ÷ 18.32 = ? + 25.022
12.03 x 4.21 +19.95% of 300.05 = ?
(660.05) ÷ 120.04% of (55.022/2.24) = (? ÷ 10.02)
(44.85% of 799.77 - √143.84)² ÷ (9/11 × 76.77) = ?
√2023.85 + (24.77% of 1999.73) - (3/8 of 799.91) = ?
16.01(? × 8.09 ÷ 16.09) = 3.01 of 69.69 + 14.12 of 4.01 - 100.998 of 2.19
