Question
A buffalo alone can plough field ‘A’ in 15 days. A
Bull alone can plough the field ‘A’ in 25 days. Find the number of days taken by 2 bulls and 3 buffalo to together plough field ‘B’ that is 26% larger than field ‘A’?Solution
Let the total work done to plough field ‘A’ = 75 units (LCM of 15 and 25) Then, efficiency of a buffalo = (75/15) = 5 units/day Efficiency of a bull = (75/25) = 3 units/day Total work required to plough field ‘B’ = 75 × 1.26 = 94.5 units Combined efficiency of 2 bulls and 3 buffalo = 3 × 2 + 3 × 5 = 21 units So, number of days required to plough field ‘B’ = 94.5/21 = 4.5 days
I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y
I. 96y² - 76y – 77 = 0
II. 6x² - 19x + 15 = 0
I. x2 + 91 = 20x
II. 10y2 - 29y + 21 = 0
I. 4x² - 21 x + 20 = 0
II. 8y² - 22 y + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. Â 2(x+2)+ 2(-x)=5
II. Â (1/(y+1)+ 1/(y+5))=(1/(y+2)+ Â 1/(y+4))
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 45x + 450 = 0
Equation 2: y² - 48y + 540 = 0�...
 If x satisfies x² – 14x + 40 = 0, find x.
I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
