Let the total work done to plough field ‘A’ = 75 units (LCM of 15 and 25) Then, efficiency of a buffalo = (75/15) = 5 units/day Efficiency of a bull = (75/25) = 3 units/day Total work required to plough field ‘B’ = 75 × 1.26 = 94.5 units Combined efficiency of 2 bulls and 3 buffalo = 3 × 2 + 3 × 5 = 21 units So, number of days required to plough field ‘B’ = 94.5/21 = 4.5 days
I. 195x² - 46x - 21 = 0
II. 209y² + 7y - 12 = 0
I. 4x2 + 9x - 9 = 0
II. 4y2 - 19y + 12 = 0
I. 6x2 – 7x - 20 = 0
II. 3y2 - y - 14 = 0
I). p2 + 17p - 234 = 0
II). q2 - 21q + 108 = 0
I. 15y2+ 4y – 4 = 0
II. 15x2+ x – 6 = 0
Quantity I: The cash price of a notebook is Rs. 100 but is can also be purchased on 11 monthly equal instalments of Rs. 10 each. Find rate of S.I.?
...Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 135 = 0
Equation 2: y² - 26y + 153 = 0
I. 4x² - 21x + 20 = 0
II. 8y² - 22y + 15 = 0
I. 18p²- 21p + 6 = 0
II. 16q² - 24q +9 = 0
(i) 2x² – 9x + 10 = 0
(ii) 4y² – 12y + 9 = 0
