Question

    What is the least 4-digit number which leaves a remainder

    of 5 when divided by both 28 and 36?
    A 1012 Correct Answer Incorrect Answer
    B 1350 Correct Answer Incorrect Answer
    C 1013 Correct Answer Incorrect Answer
    D 1022 Correct Answer Incorrect Answer

    Solution

    ATQ,

    LCM of 28 and 36 = 252

    Smallest 4-digit multiple of 252 = 4 × 252 = 1008

    Required number = 1008 + 5 = 1013

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