Question
Aman, Rahul and Pratik working together completed a job
in 10 days. The ratio of their efficiencies is 5: 4 : 3. How many days will be required by the fastest worker alone to complete the whole work?Solution
Ratio of efficiencies = 5 : 4 : 3 Ratio of time required = 1/5 : 1/4 : 1/3 = 12 : 15 : 20 Suppose Aman, Rahul and Pratik complete the work in 12x, 15x, 20x days respectively. Then, 1/(12 x) + 1/( 15 x) + 1/( 20 x) = 1/10 (5x+4x+3x)/60x = 1/10 12/60x = 1/10 x = (12×10)/60 = 2 days Hence, the fastest worker Aman can complete the work = 12x = 12 × 2 = 24 days
What will come in place of the question mark (?) in the following series?
75, 219, 388, ?, 809, 106516.12 × 15.94 + 654.92 – 344.83 = ?× 5.95
660, 653, 639, 618, 590, ?
120, 126, 138, 162, ?, 306
11          20          ?             64          112        192
...Find the missing term in the series:
2, 5, 11, 23, 47, ?
580 557 528 497 ? 419
17, 38, 123, 508, ?, 15426
What will come in place of the question mark (?) in the following series?
55, 176, 320, ?, 685, 910
161Â Â Â Â 173Â Â Â Â Â Â 191 Â Â Â Â Â Â 215Â Â Â Â Â Â 245 Â Â Â Â Â Â ?
...
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