Question
A, B, and C together can do a work alone in 12 days, 18
days, and 54 days respectively. A alone starts the work and work for 3 days and leaves the work, then B alone does the work for 8 days and leaves the work. If remaining work is done by C alone then for how many days has C worked?Solution
Total work = LCM of 12, 18 and 54 = 108 units Unit per day of A = 108/12 = 9 Unit per day of B = 108/18 = 6 Unit per day of C = 108/54 = 2 Units of work done by A in 3 days = 9 × 3 = 27 units Units of work done by B in 8 days = 8 × 6 = 48 units Remaining work = 108 – (27 + 48) = 33 units So, C has worked for 33/2 = 16.5 days
230 192 172 ? 122 100
...What value should come in the place of (?) in the following number series?
64, 80, 104, ?, 176, 224
97, 106, ?, 195, 411, 460
What will come in place of the question mark (?) in the following series?
29, 42, ?, 95, 135, 184
Find the missing term:
2, 6, 15, 31, 56, ?
32   48   96   ?   720   2520
82, 98, 130, 178, 242, ?
4 10 ? 62.5 156.25 390.625
...140, 146, 170, 224, ?, 470
7 47 ? 223 359 527
...
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