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ATQ, Let the present age of ‘Krishna’ = ‘y’ years According to the question, {(y + 6)/(y – 2)} = (3/2) Or, 2y + 12 = 3y – 6 So, y = 18 Present age of ‘Gaurav’ = 18 + 14 = 32 years So, present age of ‘Juju’ = (18 + 32)/2 = 25 years
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 34x + 285 = 0
Equation 2: y² - 26y + 165 = 0
I. 84x² - 167x - 55 = 0
II. 247y² + 210y + 27 = 0
I. 2x² - 12x + 16 = 0
II. 4y² - 8y - 12 = 0
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 20x + 96 = 0
Equation 2: y² - 18y + 72 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 34x + 288 = 0
Equation 2: y² - 29y + 210 = 0
I. 12x2- 55x + 63 = 0
II. 10y2- 47y + 55 = 0
1.3wx = 40 – wy
2. b2 = 2b + p
3. d2 + d = q
Now, observe the given conditions:
One root of equation...
I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
