Question
A, B, and C together can do a work alone in 10 days, 45
days, and 90 days respectively. A alone starts the work and work for 3 days and leaves the work, then B alone does the work for 8 days and leaves the work. If remaining work is done by C alone then for how many days has C worked?Solution
Total work = LCM of 10, 45 and 90 = 90 units Unit per day of A = 90/10 = 9 Unit per day of B = 90/45 = 2 Unit per day of C = 90/90 = 1 Units of work done by A in 3 days = 9 × 3 = 27 units Units of work done by B in 8 days = 8 × 2 = 16 units Remaining work = 90 – (27 + 16) = 47 units So, C has worked for 47/1 = 47 days
What will come in place of the question mark (?) in the following series?
1528, 1416, 1204, ?, 480, -32
143 Â Â Â Â 119Â Â Â Â 107Â Â Â Â 101Â Â Â Â Â 98Â Â Â Â ?
96 89 ? 90 94 91
...What value should come in the place of (?) in the following number series?
19, 235, 260, 324, 333, ?
What will come in place of the question mark (?) in the following series?
305...
In each of the following number series, one term is missing. Find the missing term.
3, 5, 20, 24, 144, 150, ?
1029, 1030, 1039, 1064, ?, 1194
75, 80, 95, ?, 155, 200
What will come in place of the question mark (?) in the following series?
1515, 184, ?, 455, 967, 624
7 29 61 ? 211 349
...
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