Question
A alone can complete 40% of a work in 18 days while B
takes 15 days more than A to complete it. If B and C together can complete the work in 20 days, then find the time taken by C alone to complete the same work.Solution
Time taken by A alone to complete the entire work = 18/0.4 = 45 days Time taken by B alone to complete the entire work = 45 + 15 = 60 days Let the total work = L.C.M of 45, 60 and 20 = 180 units Then, efficiency of B = (180/60) = 3 units/day Combined efficiency of B and C = (180/20) = 9 units/day So, efficiency of C alone = 9 – 3 = 6 units/day So, time taken by C alone to complete the entire work = (180/6) = 30 days
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 41x² - 191x + 150 = 0
Equation 2: 43y² - 191y + ...
I. 2x² - 12x + 16 = 0  Â
II. 4y² - 8y - 12 = 0  Â
Equation 1: x² - 180x + 8100 = 0
Equation 2: y² - 170y + 7225 = 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer Â
I. 7x² - 19x + 10 = 0...
I. 5x² - 24 x + 28 = 0  Â
II. 4y² - 8 y - 12= 0  Â
I. 6x2 - 41x+13=0
II. 2y2 - 19y+42=0
I. 3x2 - 14x + 15 = 0
II. 15y2 - 34 y + 15 = 0
I. 2x² + 11 x + 15 = 0  Â
II. 2y² - 19 y + 44 = 0  Â
1.3wx = 40 – wy
2. b2 = 2b + p
3. d2 + d = q
Now, observe the given conditions:
One root of equation...
I. 2y2 - 37y + 143 = 0
II. 2x2 + 15x – 143 = 0
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