Let the total work = 120 units (LCM of 20, 30 and 24) Amount of work done by Karan alone in one day = 120/20 = 6 units Amount of work done by Arjun alone in one day = 120/30 = 4 units Amount of work done by Krunal alone in one day = 120/24 = 5 units Amount of work done by Karan, Arjun and Krunal together in 3 days = 3 × (6 + 4 + 5) = 45 units Amount of work done by Arjun and Krunal together in 5 days = 5 × (4 + 5) = 45 units Remaining work = 120 – 45 – 45 = 30 units So, the time taken by Krunal alone to complete 30 units work = 30/5 = 6 days So, Krunal worked for 6 + 5 + 3 = 14 days
If A and B are complementary angles, then the value of-
sin A cos B + cos A sin B – tan A tan B + sec 2
Simplify (cos20°+sin 20°) /(cos20°-sin20°)
Simplify: sin (A + B) sin (A - B)
What is the value of cosec30° sec30°?
The minimum value of 77 sin θ + 36cosθ is
If tan A = 4/3, 0 ≤ A ≤ 90°, then find the value of sec A.
Simplifies-
(1 + tan²A) + (1+ 1 /tan²A)
[A] 1/ (sin²A-sin4 A)
[C] 1/ (cos2 A-sin4 A)
[B]...
If Sinθ + Cosθ =√2 Cos(90 -θ ), then find the value of Cotθ ?
...tan 20˚ x tan 23˚ x tan 67˚ x tan 70˚ = ?