Question
A2 type ‘P’ pipes can fill a tank in 350
hours, while B2 type ‘Q’ pipes can fill the same tank in 504 hours. (10A × 6B) type ‘P’ pipes can fill the same tank in how many hours? (Efficiency of a type P and a type Q pipe is same)Solution
A2 × 350 = B2 × 504 A2/B2 = 504/350 A2/B2 = 36/25 A/B = 6/5 A = 6B/5 (10A × 6B) type 'P' pipes = 10 × 6B/5 × 6B = 72B2 Required time = (B2 × 504)/(72 × B2) = 7 hrs
Statement: C ≤ D < E; C > F > G
Conclusions: I. F < E II. C > G
...Statement: J > H ≤ G; F < M ≤ J; G = K
Conclusion: I. M ≤ G      II. M > K
Statements: N & C, C # I, I @ L, L % Y
Conclusions: I.  C & Y                     II. L # N
...Statements: M ≤ N; O < R; O = N; S ≥ Q; N > S
Conclusions:
(i) Q < M
(ii) N ≥ Q
(iii) M > R
...Statements: R < S = K < T ≤ F; T > E; I = T ≤ W
Conclusions:
I. W > K
II. F ≥ R
III. R < F
Statements: A ≥ B ≥ Y = Z = M ≥ N ≤ E ≤ F = J
Conclusions:
I. F > Z
II. J ≤ Y
Statement: F < G; F ≥ H > I; D ≥ E > G
Conclusion:
I. I ≥ G
II. E ≥ F
Statements: L ≤ M = N ≤ O = Q; Z ≥ T > P = Q; L > R = S < V
Conclusions:
I. Z ≥ N
II. V > P
III. R < T
Statements: J > K = L ≥ M ≥ Q; N < O ≤ P < Q
Conclusions:
I. Q > N
II. J > O
Statements:
P > Q < R; T ≤ U ≤ Q > S; V ≤ W < T
Conclusions:
I). Â P > V
II). Â T = S
III). Â R > V
...