Question
Two cars of equal length are running in the same
direction at 48 kmph and 32 kmph. The faster car passes the slower car in 18 seconds. The length of each car is.Solution
Let the length of the car be x meters Relative speed = 48 – 32 = 16 kmph. Relative speed in mps =16 × 5/18 mps = 40/9 mps Time = Distance/Speed ⇒ 18 = 2x/(40/9 ) ⇒ 2x= (18 × 40)/9 ⇒ x = 40m ∴ The length of car is 40m
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