Question
A can complete a work in 16 days and B can complete it
in 24 days. They work together for 6 days, then A leaves. In how many more days will B finish the remaining work?Solution
ATQ, A’s 1-day work = 1/16 B’s 1-day work = 1/24 Together = 1/16 + 1/24 = 3/48 + 2/48 = 5/48 Work done in 6 days = 6*(5/48) = 30/48 = 5/8 Remaining work = 1 - 5/8 = 3/8 B alone rate = 1/24 Time = (3/8) ÷ (1/24) = (3/8)*24 = 9 days
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