Question
Sneha cycles to her tuition class at a speed of 20 km/h and
ends up reaching 3 hours late. Had she pedalled at 25 km/h, she would have reached exactly on time. Determine the total distance Sneha covered.Solution
ATQ,
(Let the actual time Sneha should take to reach the class = 't' hours
Let the total distance = 'd' km
We have,
20(t + 3) = 20t + 60 = d
Also,
25t = d
So, 20t + 60 = 25t
So, 5t = 60
So, t = 12
So, d = 25t = 25 × 12 = 300 km
Statements: L ≥ M = N > O, R < M ≤ P > Q
Conclusion:
I. O ≥ Q
II. R < L
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