Question
A train can normally cover 200 metres in 8 seconds. How
much distance (in km) can the train cover in 3 hours if it travels at 150% of its normal speed?Solution
ATQ,
Normal speed of the train = 200/8 = 25 m/s
150% of normal speed of the train = 25 × 1.5 = 37.5 m/s = 37.5 × 3.6 = 135 km/h
So, distance travelled in 3 hours = 135 × 3 = 405 km
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