Question
How far will 'Neha' travel by the time she catches up to
'Simran', given that 'Neha' starts 75 km behind and moves at 60 km/h while 'Simran' moves at 45 km/h?Solution
ATQ,
Relative speed of 'Neha' w.r.t 'Simran' = 60 - 45 = 15 km/h
Time taken by 'Neha' to overtake 'Simran' = (75/15) = 5 hours
So, distance covered by 'Neha' in 5 hours = 60 × 5 = 300 km
More Time and distance Questions
I. 15y2 + 4y – 4 = 0
II. 15x2 + x – 6 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 5x² = 19x – 12
II. 5y² + 11y = 12
I. x3 = 1728
II. y2 – 15y + 56 = 0
I. 40x² + 81x + 35 = 0
II. 63y² + 103y + 42 = 0
I. 35x² - 51x + 18 = 0
II. 30y² + 17y – 21 = 0
I. 2y² - 35y + 132 = 0
II. 2x² - 31x + 110 = 0
I:Â x2Â - 33x + 242 = 0
II:Â y2Â - 4y - 77 = 0
I. p²= ∛1331
II. 2q² - 21q + 55 = 0
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0
