Question
How far will 'Neha' travel by the time she catches up to
'Simran', given that 'Neha' starts 75 km behind and moves at 60 km/h while 'Simran' moves at 45 km/h?Solution
ATQ,
Relative speed of 'Neha' w.r.t 'Simran' = 60 - 45 = 15 km/h
Time taken by 'Neha' to overtake 'Simran' = (75/15) = 5 hours
So, distance covered by 'Neha' in 5 hours = 60 × 5 = 300 km
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