Question
The speed ratio of Renu and Meenu is 4:5, respectively.
Renu travels a distance of 300 km from point 'A' to 'B', while Meenu covers the same distance but in the opposite direction, from 'B' to 'A'. Renu begins her journey at 9:00 AM, whereas Meenu starts at 10:30 AM. Given that the difference in their speeds is 4 km/hr, determine the time at which they will meet during their journey.Solution
Let the speed of Renu and Meenu be 4x km/hr and 5x km/hr respectively.
ATQ,
5x - 4x = x = 4
Speed of Renu = 16 km/hr
Speed of Meenu = 20 kmhr
Distance covered by Renu in 1.5 hours (9:00 AM to 10:30 AM) = 1.5 X 16 = 24 km
Remaining distance = 300 - 24 = 276 km
Time in which both will meet = {276 ÷ (16 + 20) }= 7 hours 40 minutes
Therefore, required time = 10:30 + 7:40 = 18:10 = 6:10 PM
510.11 ÷ 16.98 × 5.14 – 119.9 = √?
( 19.95% of 799.89 ) × 12.05 = ? 2 + 18.99 × 6250 ÷ 1250
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(1560.23 ÷ 25.98) + (768.32 ÷ 23.9) + 1814.11 = ?
5466.97 - 3245.01 + 1122.99 = ? + 2309.99
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
956.41 of 45.06% = ?
12.05% of 1399. 93 + 24.95 × 15.05 - 319.04 = ?
3, 4, 10, 33, 136, ?
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