Question
A car which is traveling at a speed of 50 km/hr
increased its speed by 10 km/hr after ‘y’ hours and after that, it traveled for (y + 7) hours more. If the distance covered by the car in the last (y + 7) hours is 680 km, then find the distance covered by it in the first ‘y’ hours.Solution
ATQ, (50 + 10) × (y + 7) = 680 Or, 60 × (y + 7) = 680 Or, y + 7 = 11 Or, y = 4 Therefore, required distance traveled = 50 × 4 = 200 km
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