Question
On travelling with 25% less speed than his actual speed,
Vikram reached the destination 3.5 hours late. Find the time taken by him to reach his destination while travelling with his actual speed.Solution
ATQ, Let the actual speed of Vikram be βsβ km/hr. And, actual time taken by him to reach his destination is βtβ hours. So, total distance covered by Vikram in βtβ hours = {s Γ t} km --------- (1) Also, Distance covered by Vikram while travelling at 25% less speed = 75% of s Γ (t + 3.5) = 0.75 Γ s Γ (t + 3.5) km --------- (2) From equation (1) and (2), we have s Γ t = (3/4) Γ s Γ (t + 3.5) Or, 4st = 3st + 10.5s Or, st = 10.5s So, t = 10.5 So, required time = 10.5 hours
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
17% of 250 + ? = 108
32 + 26 Γ (484 Γ· 44) + 450 Γ· 9 = ?Β
40 Γ 5 + 27) Γ 9 = ?
What will come in the place of question mark (?) in the given expression?
193...
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
What will come in the place of question mark (?) in the given expression?
β1296 + (2/3 of 45% of 480) = ?
- Determine the value of βpβ if p = β529 + β1444
120% of 250 + 110 + 135 Γ· 5 = ?