Question
Person 'A' left the college at 7
PM at 65% of the original speed. After 30 minutes, he reached the grocery store, picked up a bag of vegetables, and then traveled towards his home. If the time taken to travel from home to the college at regular speed is 2 hours, find the ratio of the distance covered by 'A' from the college to the grocery store to the distance covered by 'A' from the grocery store to his home.Solution
ATQ, Let the speed is 'd' Kmph Distance covered by A from home to College = 2d Km 65% of the original speed, d × (65/100) = 0.65d Distance covered from College to Store = 0.65d × (30/60) = 0.325d Distance covered from Store to home = 2d - 0.325d = 1.675d Required ratio = 0.325d:1.675d = 13:67
More Time and distance Questions
What will come in the place of question mark (?) in the given expression?
75% of (√64 × 8 - 16) × ? = 15²
(8.6 × 8.6 + 4.8 × 4.8 + 17.2 × 4.8) ÷ (8.62 – 4.82 ) = ? ÷ 19
6 0 - 20 [8 + 12 {8-8 (20-12)+20}-40] ÷ 16 =?
- What will come in place of the question mark (?) in the following questions?
144÷12+18×2=? 75% of 65% of 7/5 of 2420 = ?
Find the simplified value of the given expression:
1.82 + 2.42 + 1.52 - 1.8 x 2.4 - 2.4 x 1.5 - 1.8 x 1.5
(√ 196 x √ 36 x √ 100) = ?% of 200
72% of 486 – 64% of 261 = ?
35% of 240 – 6 2 = ? 2 – √256
