Question
A cyclist usually takes 6 hours
to cover 240 kilometres. Find the time taken by the cyclist to cover the same distance if he travels at 25% of his usual speed.Solution
ATQ, Usual speed of the cyclist = (240/6) = 40 km/h New speed of the cyclist = 0.25 Ă— 40 = 10 km/h New time taken = (240/10) = 24 hours Alternate Solution: Let the usual speed of the cyclist be 10x km/hr. Therefore, decreased speed = 2.5x km/hr Since the distance covered is the same and time taken is inversely proportional to the speed: Ratio of time taken with usual speed to time taken with reduced speed = 6:24 = 1:4 Required time taken = 6 Ă— (4/1) = 24 hours
A man goes to Mumbai from Pune at a speed of 4 km/hr and returns to Pune at speed of 6 km/hr. What is his average speed of the entire journey?
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