Question
A superbike takes 84 minutes to cover 112 km. If the
speed of the superbike is decreased by 20 km/h, then find the time taken by the superbike to cover the same distance.Solution
Speed of the superbike = (112/84) x 60 = 80 km/h New speed of the superbike = 80 - 20 = 60 km/h So, required time = (112/60) x 60 = 112 minutes or 1 hour and 52 minutes
I. p2 – 15p + 56 = 0
II. q2 + 2q – 63 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
I. 4x² -  15x + 9 = 0
II. 20y² -  23y + 6 = 0
Solve the quadratic equation:
5x² − 13x + 6 = 0
I. 2x2 – 5x - 12 = 0
II. y2 – 11y + 30 = 0
I. 2 x² - 15 + 18 = 0
II. x²- 3 + 2 = 0
...I. 18p²- 21p + 6 = 0   Â
II. 16q² - 24q +9 = 0
I. 99x² + 161 x + 26 = 0
II. 26 y² + 161 y + 99 = 0
Roots of the quadratic equation 2x2 + x – 528 = 0 is
l). p² - 29p + 204 = 0
ll). q² + 4q - 221 = 0